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3x^2+48x+144=0
a = 3; b = 48; c = +144;
Δ = b2-4ac
Δ = 482-4·3·144
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-24}{2*3}=\frac{-72}{6} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+24}{2*3}=\frac{-24}{6} =-4 $
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